{"id":5721,"date":"2023-06-18T15:42:32","date_gmt":"2023-06-18T08:42:32","guid":{"rendered":"https:\/\/146.\/?p=5721"},"modified":"2024-04-19T20:08:26","modified_gmt":"2024-04-19T13:08:26","slug":"keo-chap-05-1-la-gi","status":"publish","type":"post","link":"https:\/\/146.\/keo-chap-05-1-la-gi\/","title":{"rendered":"K\u00e8o ch\u1ea5p 0.5\/1 l\u00e0 g\u00ec? B\u00ed quy\u1ebft soi k\u00e8o ch\u00ednh x\u00e1c nh\u1ea5t"},"content":{"rendered":"
K\u00e8o ch\u1ea5p 0.5\/1 l\u00e0 g\u00ec? Trong l\u0129nh v\u1ef1c c\u00e1 \u0111\u1ed9 b\u00f3ng \u0111\u00e1, nh\u00e0 c\u00e1i \u0111\u01b0a ra nhi\u1ec1u lo\u1ea1i k\u00e8o kh\u00e1c nhau \u0111\u1ec3 ng\u01b0\u1eddi ch\u01a1i l\u1ef1a ch\u1ecdn. M\u1ed7i lo\u1ea1i k\u00e8o \u0111\u1ec1u c\u00f3 quy t\u1eafc v\u00e0 gi\u00e1 tr\u1ecb ri\u00eang bi\u1ec7t. Trong s\u1ed1 \u0111\u00f3, k\u00e8o n\u00e0y l\u00e0 m\u1ed9t trong nh\u1eefng lo\u1ea1i k\u00e8o nh\u1eadn \u0111\u01b0\u1ee3c s\u1ef1 quan t\u00e2m \u0111\u1eb7c bi\u1ec7t t\u1eeb ng\u01b0\u1eddi ch\u01a1i. \u0110\u1ec3 hi\u1ec3u r\u00f5 h\u01a1n v\u1ec1 t\u1ef7 l\u1ec7 k\u00e8o 0.5\/1 v\u00e0 c\u00e1ch ph\u00e2n t\u00edch t\u1ef7 l\u1ec7 k\u00e8o n\u00e0y \u0111\u1ec3 c\u00f3 l\u1ee3i th\u1ebf chi\u1ebfn th\u1eafng. Ch\u00fang ta h\u00e3y kh\u00e1m ph\u00e1 trong b\u00e0i vi\u1ebft d\u01b0\u1edbi \u0111\u00e2y c\u00f9ng Kubet<\/strong><\/a> nh\u00e9!<\/p>\n K\u00e8o ch\u1ea5p 0.5\/1 N\u00f3 c\u00f2n \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 3\/4 tr\u00e1i hay 0.75. \u0110\u00e2y l\u00e0 m\u1ed9t trong nh\u1eefng lo\u1ea1i k\u00e8o ch\u1ea5p \u0111\u01b0\u1ee3c xem l\u00e0 v\u00f4 c\u00f9ng ph\u1ed5 bi\u1ebfn tr\u00ean th\u1ecb tr\u01b0\u1eddng c\u00e1 c\u01b0\u1ee3c Ch\u00e2u \u00c1. T\u01b0\u01a1ng t\u1ef1 nh\u01b0 c\u00e1c t\u1ef7 l\u1ec7 c\u01b0\u1ee3c truy\u1ec1n th\u1ed1ng kh\u00e1c, t\u1ef7 l\u1ec7 c\u01b0\u1ee3c 0.5\/1 c\u00f3 ngh\u0129a l\u00e0 n\u1ebfu b\u1ea1n \u0111\u1eb7t c\u01b0\u1ee3c v\u00e0o \u0111\u1ed9i b\u00f3ng thua. T\u1ef7 l\u1ec7 c\u01b0\u1ee3c c\u00f2n l\u1ea1i s\u1ebd l\u00e0 0,75.<\/p>\nK\u00e8o ch\u1ea5p 0.5\/1 l\u00e0 g\u00ec?<\/strong><\/h2>\n